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31 lines
577 B
31 lines
577 B
#include <bits/stdc++.h>
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using namespace std;
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const int N = 30010;
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int n, m;
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int f[N];
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/*
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将原问题做如下转化
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总钱数相当于背包总容量
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每件物品的价格相当于体积
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每件物品的价格乘以重要度相当于价值
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那么就变成了经典的01背包问题。
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*/
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int main() {
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cin >> m >> n;
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for (int i = 0; i < n; i++) {
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int v, w;
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cin >> v >> w;
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w *= v;
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for (int j = m; j >= v; j--)
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f[j] = max(f[j], f[j - v] + w);
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}
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cout << f[m] << endl;
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return 0;
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} |