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#include <bits/stdc++.h>
using namespace std;
// 推规律，1行j列为j，n行j列为3n-j-1，1行i列为4n-i-2，n行i列为n+i-1。
int dfs(int n, int i, int j) {
if (i == 1) return j;
if (i == n) return 3 * n - j - 1;
if (j == 1) return 4 * n - i - 2;
if (j == n) return n + i - 1;
return dfs(n - 2, i - 1, j - 1) + (n - 1) * 4;
}
int main() {
int n, a, b;
cin >> n >> a >> b;
cout << dfs(n, a, b) << endl;
return 0;
