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# include <bits/stdc++.h>
using namespace std ;
typedef long long LL ;
int a [ 10 ] ;
/**
总结：
do {
} while (next_permutation(a + 1, a + 10));
1、只能配合数组使用
2、注意范围是前闭后开。
3、效果是可以所有可能出现的全排列
*/
int main ( ) {
LL A , B , C , x , y , z , cnt = 0 ;
cin > > A > > B > > C ;
for ( int i = 1 ; i < = 9 ; i + + ) a [ i ] = i ;
do {
x = a [ 1 ] * 100 + a [ 2 ] * 10 + a [ 3 ] ;
y = a [ 4 ] * 100 + a [ 5 ] * 10 + a [ 6 ] ;
z = a [ 7 ] * 100 + a [ 8 ] * 10 + a [ 9 ] ;
if ( x * B = = y * A & & y * C = = z * B ) //避免除法，
printf ( " %lld %lld %lld \n " , x , y , z ) , cnt + + ;
} while ( next_permutation ( a + 1 , a + 10 ) ) ;
if ( ! cnt ) printf ( " No!!! " ) ;
return 0 ;
}
