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#include <bits/stdc++.h>
using namespace std;
const int N = 110;
int n, r;
int a[N], idx;
/**
测试数据：
-15 -2
结果 110001
*/
int main() {
cin >> n >> r;
cout << n << "=";
//数位分离
while (n) {
a[idx] = n % r; //余数
n /= r; //商
if (a[idx] < 0) { //余数不能是负的,如果是负的，需要借位
a[idx] += (-r); //借位增加（-r）
n++; //商++
}
idx++;
//倒序
for (int i = idx - 1; i >= 0; i--)
if (a[i] >= 10)
printf("%c", (char) ('A' + a[i] - 10));
else printf("%d", a[i]);
cout << "(base" << r << ")";
return 0;
