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#include <bits/stdc++.h>
using namespace std;
int n, w;
const int N = 1e5 + 10;
int a[N];
// 能通过一部分，50%左右，不能AC，原因是每次都排序O(n*n*logn)
int main() {
cin >> n >> w;
for (int i = 1; i <= n; i++) { // 1e5 *600=6e7
cin >> a[i]; // a[i]<=600
int cnt = max(1, i * w / 100); // 1,2
sort(a + 1, a + i + 1); // 从小到大排序
printf("%d ", a[i - cnt + 1]); // 大的在后面
}
return 0;
