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#include <bits/stdc++.h>
using namespace std;
const int N = 110;
int a[N];
int st[10];
struct Node {
int st, ed;
};
vector<Node> q;
/*
5
1 2 3 3 2
*/
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) cin >> a[i]; // 密码数组
for (int i = 1; i <= n; i++) {
if (!st[a[i]]) {
st[a[i]] = 1;
for (int j = n; j; j--)
if (a[i] == a[j]) {
q.push_back({i, j});
break;
}
}
}
// 从左到右枚举,所以,不再需再进行按左端点排序,现在就是按左端点排序完的
for (int i = 0; i < q.size(); i++) cout << q[i].st << " " << q[i].ed << endl;
return 0;
}