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38 lines
1001 B
38 lines
1001 B
#include <bits/stdc++.h>
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using namespace std;
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int m[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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bool check(int d) {
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int year = d / 10000;
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int month = (d % 10000) / 100;
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int day = d % 100;
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// 求闰年 : 四年一闰，百年不闰，千年闰
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if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) m[2] = 29;
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// 判断日,月是否符合
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if (day > m[month]) return false;
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if (month > 12) return false;
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return true;
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}
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int main() {
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int date1, date2;
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cin >> date1 >> date2;
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int ans = 0; // 答案
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// 枚举1000 ~ 9999的数字 , 因为这里是回文数，只要要枚举出来一半即可
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for (int i = 1000; i <= 9999; i++) {
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// 将另一半算出来
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int r = i;
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for (int j = i; j; j /= 10) r = r * 10 + j % 10; // 短除法求出位数，然后加上去
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if (date1 <= r && r <= date2 && check(r)) ans++;
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}
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cout << ans << endl;
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return 0;
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} |