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#include <bits/stdc++.h>
using namespace std;
const int N = 110;
// 依次枚举每个空格，然后统计八个方向上的相邻格子有没有地雷即可
int n, m;
char g[N][N];
int main() {
cin >> n >> m;
for (int i = 0; i < n; i++) cin >> g[i];
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++)
if (g[i][j] == '*')
cout << '*';
else {
int s = 0;
// 8个方向一般玩的是9宫格，然后放弃自己
for (int x = i - 1; x <= i + 1; x++)
for (int y = j - 1; y <= j + 1; y++)
if (x != i || y != j) {
if (x >= 0 && x < n && y >= 0 && y < m && g[x][y] == '*') s++;
}
cout << s;
cout << endl;
return 0;
