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# include <bits/stdc++.h>
using namespace std ;
# define int long long
# define endl '\n'
const int MOD = 1e9 + 7 ;
// 60 ms
// 欧拉筛
const int N = 1e6 + 10 ;
int primes [ N ] , cnt ; // primes[]存储所有素数
bool st [ N ] ; // st[x]存储x是否被筛掉
void get_primes ( int n ) {
memset ( st , 0 , sizeof st ) ;
cnt = 0 ;
for ( int i = 2 ; i < = n ; i + + ) {
if ( ! st [ i ] ) primes [ cnt + + ] = i ;
for ( int j = 0 ; primes [ j ] * i < = n ; j + + ) {
st [ primes [ j ] * i ] = true ;
if ( i % primes [ j ] = = 0 ) break ;
}
}
}
signed main ( ) {
int n ;
cin > > n ;
// 步骤1:筛质数
get_primes ( n ) ;
// 步骤2: 阶乘质因子分解
int res = 1 ;
for ( int i = 0 ; i < cnt ; i + + ) {
int p = primes [ i ] ;
int s = 0 ;
for ( int j = n ; j ; j / = p ) s + = j / p ; // 应除尽除
// 步骤3: 约数个数公式.因为通过公式推导我们知道, 不是n!,而是(n!)^2,所以,是(2*s+1)做为累乘因子
res = res * ( 2 * s + 1 ) % MOD ;
}
cout < < res < < endl ;
}