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#include <bits/stdc++.h>
using namespace std;
#define int long long
#define endl "\n"
const int MOD = 1e9 + 7;
const int N = 4;
int n;
// 矩阵乘法
void mul(int a[][N], int b[][N], int c[][N]) {
int t[N][N] = {0};
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
for (int k = 0; k < N; k++)
t[i][j] = (t[i][j] + (a[i][k] * b[k][j] % MOD)) % MOD;
memcpy(c, t, sizeof t);
}
void solve() {
int b[N][N] = {1, 1, 1}, m[N][N] = {0};
m[0][2] = m[1][0] = m[2][1] = m[2][2] = 1;
for (int i = n - 3; i; i >>= 1) {
if (i & 1) mul(b, m, b);
mul(m, m, m);
}
printf("%lld\n", b[0][2]);
}
signed main() {
int T;
cin >> T;
while (T--) {
cin >> n;
if (n <= 3) {
printf("1\n");
continue;
}
solve();
}
}