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39 lines
901 B
39 lines
901 B
#include <bits/stdc++.h>
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using namespace std;
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const int N = 20;
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int f[N];
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int w[N];
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int path[N][N];
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//致敬墨染空大神
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void out(int i, int j) {
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if (i == 0) return; //走出界就完事了
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int k = path[i][j];
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out(i - 1, j - k); //利用递推的栈机制，后序输出，太强了~
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printf("%d %d\n", i, k);
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}
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int main() {
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int n, m;
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scanf("%d%d", &n, &m);
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= m; j++)
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scanf("%d", &w[j]);
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for (int j = m; j; j--)
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for (int k = 1; k <= j; k++) {
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int val = f[j - k] + w[k];
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if (val >= f[j]) {
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f[j] = val;
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//在状态转移时，记录路径
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path[i][j] = k;
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}
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}
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}
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//输出结果
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printf("%d\n", f[m]);
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//输出路径
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out(n, m);
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return 0;
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}
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