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#include <bits/stdc++.h>
using namespace std;
const int N = 1000010;
#define int long long
#define endl "\n"
int a[N], s[N];
int n, k; // n个城市，传送半径为k
signed main() {
cin >> n >> k; // n个城市，传送半径为k
for (int i = 1; i < n; i++) { // 以起点为线段命名的编号,所以1~n共n个城市,其实是n-1条线段
cin >> a[i]; // 走这条路要耗费时间a[i]
s[i] += s[i - 1] + a[i]; // 前缀和
}
int ans = s[n - 1]; // sum总和
// 这是在枚举什么？
for (int i = k; i < n; i++) ans = min(ans, s[n - 1] - (s[i] - s[i - k]));
cout << ans << endl;
