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#include <bits/stdc++.h>
using namespace std;
const int N = 10005;
/*
文件名：petroleum
题目：洛谷 P1862 输油管道问题
题目网址：https://www.luogu.com.cn/problem/P1862
输入：
5
1 2
2 2
1 3
3 -2
3 3
输出：
6
*/
int n, a[N]; // a[0..n-1]。第i口油井的纵坐标在a[i]
int main() {
// 输入数据
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i] >> a[i]; // 横坐标说没有用的，可以直接抛弃掉
// 排序
sort(a, a + n);
// 两端对称取长短。中位数原理。
int sum = 0;
for (int i = 0, j = n - 1; i <= j; i++, j--) sum += a[j] - a[i];
cout << sum << endl;
return 0;
}
