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25 lines
518 B
25 lines
518 B
#include<bits/stdc++.h>
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using namespace std;
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const int N = 2000010;
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int b[N]; //灯的状态
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double a; //1-1000的实数
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int n; //操作数量
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int t; //倍数
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int main() {
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cin >> n;
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for (int i = 1; i <= n; i++) {
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cin >> a >> t;
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for (int j = 1; j <= t; j++) {
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int x = a * j;
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b[x] = !b[x];
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}
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}
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for (int i = 1; i < N; i++)
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if (b[i]) {
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printf("%d ", i);
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break;
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}
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return 0;
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} |