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#include <bits/stdc++.h>
using namespace std;
const int N = 1010;
int n, m;
int v[N], w[N];
int f[N];
string s[N];
// 如果扩展问题：取得最大值时，选择的是哪些物品？
// D:\python\TangDou\LanQiao12ShengSai\BC4.jpg
int main() {
// 物品个数n
cin >> n >> m; // m:背包容积，就是大V
for (int i = 1; i <= n; i++) cin >> w[i] >> v[i];
for (int i = 1; i <= n; i++)
for (int j = m; j >= w[i]; j--) {
if (f[j - w[i]] + v[i] > f[j]) {
f[j] = f[j - w[i]] + v[i];
s[j] = s[j - w[i]] + " " + (char)(i + '0');
}
cout << f[m] << endl;
cout << s[m] << endl;
return 0;
