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#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
/*
思想：底数相同的两个数相乘底数不变，指数相加。
通过log10(x)得到指数，依次相加即可，即可以得到阶乘的位数
*/
const int N = 10000010;
int a[N];
int main() {
//预处理出阶乘的位数
double x = 0;
for (int i = 1; i < N; i++) {
x += log10((double)i); // POJ对于log10(i)会报编译错误，需要转为double
a[i] = x + 1;
}
// T次询问
int T;
scanf("%d", &T);
while (T--) {
int n;
scanf("%d", &n);
printf("%d\n", a[n]);
return 0;
