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#include <bits/stdc++.h>
using namespace std;
int t;
//最大公约数
int gcd(int x, int y) {
return y ? gcd(y, x % y) : x;
}
int main() {
cin >> t;
while (t--) {
int n;
cin >> n;
//一次读入第一个和第二个
int a, b;
cin >> a >> b;
b /= gcd(a, b);//去掉a,b公因子，目标是b=1,a已经发近挥不出来力量啦
//逐个读入，逐个约分
for (int i = 3; i <= n; i++) {
int x;
cin >> x;
b /= gcd(x, b);
if (b == 1) cout << "Yes" << endl;
else cout << "No" << endl;
return 0;
