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# include <bits/stdc++.h>
using namespace std ;
const int N = 210 ; //2*n+10
char a [ N ] ;
int n ;
//输出当前行
void print ( ) {
for ( int i = 1 ; i < = 2 * n + 2 ; i + + ) cout < < a [ i ] ;
cout < < endl ;
}
//递归函数
void dfs ( int x ) {
//输出当前行
print ( ) ;
//大于4时, 可以进行递归
if ( x > 4 ) {
swap ( a [ x ] , a [ 2 * x + 1 ] ) , swap ( a [ x + 1 ] , a [ 2 * x + 2 ] ) ; // 中间的o*与最后--交换
//输出
print ( ) ;
swap ( a [ x ] , a [ 2 * x - 1 ] ) , swap ( a [ x + 1 ] , a [ 2 * x ] ) ; //将最右边的**与--位置交换
//数值-1, 进行递归
dfs ( x - 1 ) ;
return ;
}
//等于4时, 是一个固定的路线
swap ( a [ 4 ] , a [ 9 ] ) , swap ( a [ 5 ] , a [ 10 ] ) ;
print ( ) ;
swap ( a [ 4 ] , a [ 8 ] ) , swap ( a [ 5 ] , a [ 9 ] ) ;
print ( ) ;
swap ( a [ 2 ] , a [ 8 ] ) , swap ( a [ 3 ] , a [ 9 ] ) ;
print ( ) ;
swap ( a [ 2 ] , a [ 7 ] ) , swap ( a [ 3 ] , a [ 8 ] ) ;
print ( ) ;
swap ( a [ 1 ] , a [ 7 ] ) , swap ( a [ 2 ] , a [ 8 ] ) ;
print ( ) ;
}
int main ( ) {
cin > > n ;
//初始化棋盘
for ( int i = 1 ; i < = n ; i + + ) a [ i ] = ' o ' ; //前n个是o
for ( int i = 1 ; i < = n ; i + + ) a [ n + i ] = ' * ' ; //中间n个是*
for ( int i = 1 ; i < = 2 ; i + + ) a [ 2 * n + i ] = ' - ' ; //最后两个是-
//递归
dfs ( n ) ;
return 0 ;
}