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#include <bits/stdc++.h>
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using namespace std;
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typedef long long LL;
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int x[4] = {1, 2, 3, 4};
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const int N = 110;
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int a[N][4];
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int size;
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//填充一个全排列二维数组
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void fill_qpl() {
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do {
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a[size][0] = x[0], a[size][1] = x[1], a[size][2] = x[2], a[size++][3] = x[3];
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} while (next_permutation(x, x + 4));
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}
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int bucket[5];
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bool check(int a[4], int b[4], int c[4], int d[4]) {
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//左上
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memset(bucket, 0, sizeof bucket);
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bucket[a[0]]++, bucket[a[1]]++, bucket[b[0]]++, bucket[b[1]]++;
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for (int i = 1; i <= 4; i++)if (bucket[i] != 1) return false;
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//右上
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memset(bucket, 0, sizeof bucket);
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bucket[a[2]]++, bucket[a[3]]++, bucket[b[2]]++, bucket[b[3]]++;
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for (int i = 1; i <= 4; i++)if (bucket[i] != 1) return false;
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//左下
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memset(bucket, 0, sizeof bucket);
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bucket[c[0]]++, bucket[c[1]]++, bucket[d[0]]++, bucket[d[1]]++;
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for (int i = 1; i <= 4; i++)if (bucket[i] != 1) return false;
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//右下
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memset(bucket, 0, sizeof bucket);
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bucket[c[2]]++, bucket[c[3]]++, bucket[d[2]]++, bucket[d[3]]++;
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for (int i = 1; i <= 4; i++)if (bucket[i] != 1) return false;
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//竖着也需要检查噢~
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for (int k = 0; k < 4; k++) {
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memset(bucket, 0, sizeof bucket);
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bucket[a[k]]++, bucket[b[k]]++, bucket[c[k]]++, bucket[d[k]]++;
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for (int i = 1; i <= 4; i++)if (bucket[i] != 1) return false;
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}
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return true;
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}
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int cnt;
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int main() {
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//填充
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fill_qpl();
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for (int i = 0; i < size; i++)
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for (int j = 0; j < size; j++)
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for (int k = 0; k < size; k++)
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for (int p = 0; p < size; p++) {
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//四行数据
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//a[i],a[j],a[k],a[p] 是否可以构成数独?
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//构建的矩阵，切割成四块，每块用桶的思路看看是不是满足1，2，3，4分布
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if (i == j || i == k || i == p || j == k || j == p || k == p) continue;
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if (check(a[i], a[j], a[k], a[p])) {
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//输出
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for (int m = 0; m < 4; m++) cout << a[i][m] << " ";
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cout << endl;
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for (int m = 0; m < 4; m++) cout << a[j][m] << " ";
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cout << endl;
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for (int m = 0; m < 4; m++) cout << a[k][m] << " ";
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cout << endl;
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for (int m = 0; m < 4; m++) cout << a[p][m] << " ";
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cout << endl;
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cout << endl;
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//计数
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cnt++;
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}
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}
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cout << cnt << endl;
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return 0;
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} |
