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#include <bits/stdc++.h>
using namespace std;
int main() {
//通用mod运算，重复输出指定的1-N的方法，注意(i-1)%20-1的妙处！
for (int i = 1; i < 101; ++i) {
cout << setw(4) << (i - 1) % 20 + 1 << " ";
if (i % 20 == 0)cout << endl;
}
return 0;
