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#include <iostream>
using namespace std;
typedef long long LL;
const LL mod = 1e9 + 7;
/*
测试用例:
5 8
结果:
390625
*/
//快速幂
LL ksm(LL a, LL b) {
LL ans = 1;
a %= mod;
while (b) {
if (b & 1) ans = (ans * a) % mod;
b >>= 1; //位运算,右移1位,相当于除以2
a = (a * a) % mod;
}
return ans;
int main() {
LL a, b;
cin >> a >> b;
printf("%lld\n", ksm(a, b));
return 0;