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#include <bits/stdc++.h>
using namespace std;
#define int long long
#define endl "\n"
const int MOD = 1e9 + 7;
/*
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答案
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*/
// 求单个数值的欧拉函数值
int phi(int x) {
int res = x;
for (int i = 2; i <= x / i; i++) {
if (x % i == 0) {
res = res / i * (i - 1);
while (x % i == 0) x /= i;
}
}
if (x > 1) res = res / x * (x - 1);
return res;
}
signed main() {
int n;
while (cin >> n && n) {
// 小于n的数字中有多少个数字与n互质
int ans = n * (n - 1) / 2; // 高斯公式,(首页+末项)*项数/2
ans = (ans - phi(n) * n / 2) % MOD; // 扣除掉 phi(n)*n/2
cout << ans << endl;
}
}