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#include <bits/stdc++.h>
using namespace std;
const int N = 20;
// 学习视频
// https://www.bilibili.com/video/BV1nE411A7ST
int g[N];
// f(0)*f(n-1)+f(1)*f(n-2)+....+f(n-1)*f(0)
// 递归
int f(int n) {
if (n <= 1) return 1;
int sum = 0;
for (int i = 0; i < n; i++)
sum += f(i) * f(n - 1 - i);
return sum;
}
int main() {
// 1、递推法
g[0] = g[1] = 1;
for (int i = 2; i < N; i++)
for (int j = 0; j < i; j++)
g[i] += g[j] * g[i - 1 - j]; // 考虑思路:画括号法
for (int i = 0; i < N; i++)
cout << g[i] << endl;
// 2 、递归法
for (int i = 0; i < N; i++)
cout << f(i) << endl;
return 0;
}