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# include <bits/stdc++.h>
/*
测试用例：
5 6
1 0 1 0 0 0
0 1 0 1 0 0
1 0 0 0 1 0
0 1 0 0 0 1
1 0 1 0 0 0
测试用例II：
5 6
1 0 1 0 0 0 2 0 4 0 0 0
0 1 0 1 1 0 0 1 0 3 1 0
1 0 0 0 1 0 3 0 0 0 2 0
0 1 0 0 0 1 0 2 0 0 0 1
1 0 1 0 0 0 1 0 1 0 0 0
5 6
1 0 1 0 0 0
0 1 0 1 1 0
1 0 0 0 1 0
0 1 0 0 0 1
1 0 1 0 0 0
测试用例III：
5 6
1 0 1 0 0 0
0 1 0 1 1 0
1 0 0 0 1 0
0 1 0 1 0 1
1 0 1 0 1 0
*/
using namespace std ;
const int N = 110 ;
int a [ N ] [ N ] ;
int res ;
int main ( ) {
int n , m ;
cin > > n > > m ;
for ( int i = 1 ; i < = n ; i + + )
for ( int j = 1 ; j < = m ; j + + )
cin > > a [ i ] [ j ] ;
//直接在原数组上递推
for ( int i = n ; i > = 1 ; i - - ) //从倒数第二行开始
for ( int j = 1 ; j < = m ; j + + ) //这个需要考虑一下边界问题
if ( a [ i ] [ j ] ) //只有当前位置大于0才有考虑的价值
a [ i ] [ j ] + = a [ i + 1 ] [ j + 1 ] ; //递推式
cout < < " ==================== " < < endl ;
//打印出这个新的递推数组看看是什么情况
for ( int i = 1 ; i < = n ; i + + ) {
for ( int j = 1 ; j < = m ; j + + )
cout < < a [ i ] [ j ] < < " " ;
cout < < endl ;
}
return 0 ;
}
