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#include <bits/stdc++.h>
using namespace std;
const int N = 110;
int n, k;
int w[N], h[N];
/*
2 6
4 3
5 4
答案:
2
*/
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i++) cin >> w[i] >> h[i];
for (int i = 1;; i++) {
int cnt = 0;
for (int j = 1; j <= n; j++)
cnt += (w[j] / i) * (h[j] / i);
if (cnt == k) {
cout << i << endl;
return 0;
}
if (cnt < k) {
cout << -1 << endl;
return 0;
}
}
return 0;
}