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#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
int primes[N], cnt; // primes[]存储所有素数
bool st[N]; // st[x]存储x是否被筛掉
int factor[N]; // 存储每一个数的质因子个数
void get_primes(int n) {
memset(st, 0, sizeof st);
for (int i = 2; i <= n; i++) {
if (!st[i]) {
primes[cnt++] = i;
factor[i] = 1; // 质数的质因子个数是1
}
for (int j = 0; primes[j] * i <= n; j++) {
st[primes[j] * i] = true; // 标识primes[j] * i是个合数
factor[primes[j] * i] = factor[i] + 1; // t=primes[j]*i,那么t的质因子个数=i的质因子个数+1
if (i % primes[j] == 0) break; // 只被最小的质数因子筛掉
}
}
}
int main() {
int n, m;
cin >> n >> m;
get_primes(m);
int res = 0;
for (int i = n; i <= m; i++) {
res = max(res, factor[i]);
// printf("The count of prime factor(s) of %d is: %d\n", i, factor[i]);
}
cout << res << endl;
return 0;
}