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#include <bits/stdc++.h>
using namespace std;
// 彩带
// https://blog.csdn.net/weixin_43736974/article/details/108246801
// 从已知到未知，找规律
// 设 f(n)为有n条彩带情况下的方案数，推导
// f(1)=2 ---->全红或全白
// f(2)=2 ---->红白或白红
// f(3)=4 ---->题目中说到的
// f(4)=6 ---->再多推导一步，根据规则来。
// ...
// f(n)=f(n-1)+f(n-2)
int dp(int n) {
if (n == 1) return 2;
if (n == 2) return 2;
return dp(n - 1) + dp(n - 2);
}
int main() {
int n = 10;
cout << dp(n) << endl;
return 0;
