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# include <bits/stdc++.h>
using namespace std ;
const int N = 110 ;
int n , m , Max ;
int b1 [ N ] ; //正对角线
int b2 [ N ] ; //反对角线
//就是加一个常数增量, 将x-y与y-x转化为正数, 当然大于10的数字也可以, 但对应的数组长度要装的下才行。
const int M = 30 ;
void dfs ( int x , int y , int sum ) {
if ( x = = n + 1 ) {
//收集最大值
Max = max ( Max , sum ) ;
return ;
}
//如果这个位置可以放,那么我们可以选择放
if ( ! b1 [ x + y ] & & ! b2 [ x - y + M ] ) {
b1 [ x + y ] = 1 , b2 [ x - y + M ] = 1 ;
if ( y = = m )
dfs ( x + 1 , 1 , sum + 1 ) ;
else
dfs ( x , y + 1 , sum + 1 ) ;
b1 [ x + y ] = 0 , b2 [ x - y + M ] = 0 ;
}
//不管可以不可以放,都可以选择不放
if ( y = = m ) dfs ( x + 1 , 1 , sum ) ;
else dfs ( x , y + 1 , sum ) ;
}
int main ( ) {
cin > > n > > m ; // n行m列
dfs ( 1 , 1 , 0 ) ; //从(1,1)位置出发,0:表示已经安排好的传教士数量
cout < < Max < < endl ;
return 0 ;
}