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37 lines
650 B
37 lines
650 B
#include <bits/stdc++.h>
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using namespace std;
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const int N = 100010;
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int n;
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struct Node {
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int st;
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int ed;
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const bool operator<(const Node &W) {
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return ed < W.ed;
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}
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} w[N];
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/*
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5
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1 2 4 6 8
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3 5 7 9 10
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答案：
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3
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*/
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int main() {
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cin >> n;
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for (int i = 0; i < n; i++) cin >> w[i].st;
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for (int i = 0; i < n; i++) cin >> w[i].ed;
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sort(w, w + n);
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int ans = 0, t = 0; // 设置的个数，前一个的结束时间
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for (int i = 0; i < n; i++) {
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if (w[i].st > t) {
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t = w[i].ed;
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ans++;
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}
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}
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cout << ans << endl;
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return 0;
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} |