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26 lines
625 B
26 lines
625 B
#include <bits/stdc++.h>
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using namespace std;
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const int V[6] = {1, 5, 10, 50, 100, 500};
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int C[6];
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int A; // 要组装的货币数量
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/*
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3 2 1 3 0 2
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620
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答案：
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6
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*/
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int main() {
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for (int i = 0; i < 6; i++) cin >> C[i];
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cin >> A;
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int ans = 0;
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// 由大到小枚举
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for (int i = 5; i >= 0; i--) {
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int t = min(A / V[i], C[i]); // 能取多少，受两个条件限制：可以取的数量，包含的数量，两者取小
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A -= t * V[i]; // 扣除掉
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ans += t; // 维护结果
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}
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cout << ans << endl;
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return 0;
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} |