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#include <cstdio>
#include <iostream>
#include <vector>
#include <algorithm>
#include <cstring>
using namespace std;
// 无法AC
const int N = 1e5 + 7;
struct Node {
int l, r;
int color; // 哪种颜色的海报
int tag; // 表示这个区间的数被修改了为同一个数
} tr[N << 4];
int T, n;
int l[N], r[N];
int vis[N], ans;
int b[N], bl; // 离散化数组
void build(int u, int l, int r) {
tr[u].l = l, tr[u].r = r;
tr[u].color = 0;
tr[u].tag = -1;
if (l == r) return;
int mid = (l + r) >> 1;
build(u << 1, l, mid);
build(u << 1 | 1, mid + 1, r);
}
void pushup(int u) {
if (tr[u].tag) {
tr[u << 1].color = tr[u].color;
tr[u << 1 | 1].color = tr[u].color;
tr[u << 1].tag = tr[u << 1 | 1].tag = 1;
tr[u].tag = 0;
}
}
void modify(int u, int l, int r, int x) {
if (l <= tr[u].l && r >= tr[u].r) {
tr[u].color = x;
tr[u].tag = 1;
return;
}
pushup(u);
int mid = (tr[u].l + tr[u].r) >> 1;
if (l <= mid) modify(u << 1, l, r, x);
if (r > mid) modify(u << 1 | 1, l, r, x);
}
void query(int u, int l, int r) {
if (tr[u].tag == -1) return;
if (tr[u].tag) {
if (!vis[tr[u].color] && tr[u].color) {
++ans;
vis[tr[u].color] = 1;
}
return;
}
int mid = (l + r) >> 1;
query(u << 1, l, r);
query(u << 1 | 1, l, r);
}
/*
答案:
4
*/
int main() {
#ifndef ONLINE_JUDGE
freopen("P3740.in", "r", stdin);
#endif
// 加快读入
ios::sync_with_stdio(false), cin.tie(0);
cin >> T;
while (T--) {
cin >> n;
ans = 0;
memset(vis, 0, sizeof vis);
memset(tr, 0, sizeof tr);
bl = 0;
for (int i = 1; i <= n; i++) {
cin >> l[i] >> r[i];
b[++bl] = l[i];
b[++bl] = r[i];
b[++bl] = r[i] + 1; // 区间覆盖问题为防止缝隙问题需要r+1也入离散化数组
}
sort(b + 1, b + 1 + bl);
int tot = unique(b + 1, b + 1 + bl) - b - 1;
build(1, 1, tot);
int cnt = 0;
for (int i = 1; i <= n; i++) {
l[i] = lower_bound(b + 1, b + 1 + bl, l[i]) - b;
r[i] = lower_bound(b + 1, b + 1 + bl, r[i]) - b;
modify(1, l[i], r[i], ++cnt);
}
query(1, 1, tot);
printf("%d\n", ans);
}
return 0;
}