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#include <iostream>
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#include <algorithm>
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#include <cmath>
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#include <cstring>
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#include <vector>
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using namespace std;
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typedef long long LL;
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const int N = 10010;
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//在对 x 坐标进行升序排序时，将 k 值按降序排序，这样才能处理两个矩形贴合的情况
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struct Seg {
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LL x, y1, y2, c;
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bool operator<(const Seg &t) const {
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if (x == t.x) return c > t.c; // 1在前，-1在后，先处理入边再处理出边
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return x < t.x;
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}
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} seg[N << 1];
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struct Node {
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int l, r;
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int maxc, add;
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} tr[N << 3];
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int n, w, h;
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vector<LL> ys;
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void pushup(int u) {
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tr[u].maxc = max(tr[u << 1].maxc, tr[u << 1 | 1].maxc);
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}
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void build(int u, int l, int r) {
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tr[u] = {l, r, 0, 0};
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if (l == r) return;
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int mid = (l + r) >> 1;
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build(u << 1, l, mid);
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build(u << 1 | 1, mid + 1, r);
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}
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void pushdown(int u) {
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if (tr[u].add) {
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tr[u << 1].maxc += tr[u].add;
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tr[u << 1].add += tr[u].add;
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tr[u << 1 | 1].maxc += tr[u].add;
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tr[u << 1 | 1].add += tr[u].add;
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tr[u].add = 0;
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}
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}
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void modify(int u, int l, int r, int c) {
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if (l <= tr[u].l && tr[u].r <= r) {
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tr[u].maxc += c;
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tr[u].add += c;
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return;
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}
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pushdown(u);
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int mid = tr[u].l + tr[u].r >> 1;
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if (l <= mid) modify(u << 1, l, r, c);
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if (r > mid) modify(u << 1 | 1, l, r, c);
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pushup(u);
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}
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int find(LL x) {
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return lower_bound(ys.begin(), ys.end(), x) - ys.begin();
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}
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int main() {
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//加快读入
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ios::sync_with_stdio(false), cin.tie(0);
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while (cin >> n >> w >> h) {
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ys.clear();
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for (int i = 1; i <= n; i++) {
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LL x, y;
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int c;
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cin >> x >> y >> c;
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//区别在这里！
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/*
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需配合：
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if (x == t.x) return c > t.c; // 1在前，-1在后，先处理入边再处理出边
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*/
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seg[2 * i - 1] = {x, y, y + h - 1, c};
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//此处,x+w-1,注意：多减了一个1~
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seg[2 * i] = {x + w - 1, y, y + h - 1, -c};
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ys.push_back(y), ys.push_back(y + h - 1);
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}
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sort(ys.begin(), ys.end());
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ys.erase(unique(ys.begin(), ys.end()), ys.end());
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sort(seg + 1, seg + 1 + 2 * n);
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build(1, 0, ys.size() - 1);
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int res = 0;
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for (int i = 1; i <= 2 * n; i++) {
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res = max(res, tr[1].maxc);
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modify(1, find(seg[i].y1), find(seg[i].y2), seg[i].c);
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}
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printf("%d\n", res);
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}
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return 0;
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} |
