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#include <bits/stdc++.h>
typedef long long LL;
using namespace std;
const int N = 2e5 + 10;
int m, p;
LL c[N];
typedef long long LL;
#define lowbit(x) (x & -x)
void add(int x, LL d) {
for (int i = x; i < N; i += lowbit(i)) c[i] = max(c[i], d);
}
LL query(int x) {
LL res = 0;
for (int i = x; i; i -= lowbit(i)) res = max(res, c[i]);
return res;
}
int main() {
// 加快读入
ios::sync_with_stdio(false), cin.tie(0);
cin >> m >> p; // m次操作,p是模值
int last = 0; // last 是在这个添加操作之前最后一个询问操作的答案(如果之前没有询问操作,则 a=0
int j = m;
// j的物理含义
// 倒数第1个放到第m个位置
// 倒数第2个放到第m-1个位置
// ...
// 倒数第m个放到第1个位置
for (int i = 0; i < m; i++) {
char c;
cin >> c;
if (c == 'A') { // 表示向序列后面加一个数
LL t;
cin >> t; // t:是输入的参数
// j--:倒着存入
add(j--, (t + last) % p);
} else { // 表示这个操作是询问序列中最后 L 个数的最大数是多少
LL L;
cin >> L;
last = query(j + L); // 下次需要本次的结果
printf("%d\n", last);
}
}
return 0;
}