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#include <bits/stdc++.h>
using namespace std;
int main() {
int n = 10;
cout << (int)pow(n, 1.0 / 2) << endl;
// 输出3，理解一下：
// 10以内，可以描述为x^2的有：1^2 2^2 3^2
// 这样，就是说上面的算法，把数字1记录在内了。
return 0;
}
