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#include <bits/stdc++.h>
using namespace std;
int main() {
int x = 13;
int ans = 0;
for (int i = 30; i >= 0; i--) {
int u = x >> i & 1; //取出x的当前二进制位
ans = ans * 2 + u; //还原二进制数字为十进制
}
printf("%d", ans);
return 0;
}