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31 lines
686 B
31 lines
686 B
## $P1226$ 【模板】快速幂||取余运算
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[题目传送门](https://www.luogu.com.cn/problem/P1226)
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### 一、经验总结
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* 因为在计算快速幂过程中，会进行乘法运算，可能会爆$INT$,一般采用$LL$对所有参数进行定义
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### 二、实现代码
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```c++
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#include <bits/stdc++.h>
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using namespace std;
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typedef long long LL;
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int a, b, p;
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LL qmi(LL x, LL y, LL p) {
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LL res = 1;
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while (y) {
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if (y & 1) res = res * x % p;
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y >>= 1;
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x = x * x % p;
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}
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return res;
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}
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int main() {
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scanf("%d %d %d", &a, &b, &p);
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printf("%d^%d mod %d=%lld\n", a, b, p, qmi(a, b, p));
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return 0;
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}
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``` |