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#include <iostream>
using namespace std;
typedef long long LL;
//最大公约数,辗转相除法
int gcd(int a, int b) {
return b ? gcd(b, a % b) : a;
}
//快读
int read() {
int x = 0, f = 1;
char ch = getchar();
while (ch < '0' || ch > '9') {
if (ch == '-') f = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9') {
x = (x << 3) + (x << 1) + (ch ^ 48);
ch = getchar();
}
return x * f;
}
const int N = 2010;
int n, m, a[N][N];
void init() {
for (int i = 1; i <= 1000; i++) //互质赋值为1
for (int j = 1; j <= 1000; j++)
if (gcd(i, j) == 1) a[i][j] = 1;
for (int i = 1; i <= 1000; i++) //二维前缀和
for (int j = 1; j <= 1000; j++)
a[i][j] += a[i - 1][j] + a[i][j - 1] - a[i - 1][j - 1];
}
int main() {
init();
int m = read();
for (int i = 1; i <= m; i++) {
n = read();
printf("%d %d %d\n", i, n, a[n][n] + 2); //加上(1,0),(0,1)两个点
}
return 0;
}