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#include <bits/stdc++.h>
using namespace std;
const int N = 510;
int a[N][N];
int f[N][N]; // 记录以(x,y)坐标位置为根的子树的路径最大和
int n;
int dfs(int x, int y) {
if (f[x][y]) return f[x][y]; // 如果算过,就直接返回
if (x == n + 1) return 0; // 你们不要指望我了我是0你们该咋办就咋办吧~
if (y > x) return 0;
// 算过的都记录下来,别丢掉,左下方x+1,y,右下方x+1,y+1
f[x + 1][y] = dfs(x + 1, y);
f[x + 1][y + 1] = dfs(x + 1, y + 1);
f[x][y] = max(f[x + 1][y], f[x + 1][y + 1]) + a[x][y];
return f[x][y];
}
int main() {
cin >> n;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= i; j++)
cin >> a[i][j];
int res = dfs(1, 1);
printf("%d", res);
return 0;
}