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#include <bits/stdc++.h>
using namespace std;
const int N = 1010;
int n; // 山的个数
int a[N]; // 山的高度数组
int f[N]; // 最长上升子序列
int g[N]; // 最长下降子序列
int res;
int main() {
cin >> n;
for (int i = 1; i <= n; i++) cin >> a[i];
// 正向
for (int i = 1; i <= n; i++) {
f[i] = 1;
for (int j = 1; j < i; j++)
if (a[i] > a[j]) f[i] = max(f[i], f[j] + 1);
}
// 反向
for (int i = n; i >= 1; i--) {
g[i] = 1;
for (int j = n; j > i; j--)
if (a[i] > a[j]) g[i] = max(g[i], g[j] + 1);
}
// 每个点,都可能是两者相加的最大位置处,所以,需要枚举每个点,每个点都有资格参评最优点
// 因为最终的那个中间点左边计算了一次右边又计算了一次需要减1去重复
for (int i = 1; i <= n; i++) res = max(res, f[i] + g[i] - 1);
// 输出
printf("%d\n", res);
return 0;
}