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# include <bits/stdc++.h>
using namespace std ;
const int N = 100010 , M = 200010 ;
const int INF = 0x3f3f3f3f ;
int ans = INF ;
bool st [ N ] ;
int n ;
int h [ N ] , e [ M ] , ne [ M ] , idx ;
void add ( int a , int b ) {
e [ idx ] = b , ne [ idx ] = h [ a ] , h [ a ] = idx + + ;
}
int dfs ( int u ) {
st [ u ] = 1 ;
int sum = 1 ;
int res = 0 ;
for ( int i = h [ u ] ; ~ i ; i = ne [ i ] ) {
int v = e [ i ] ;
if ( ! st [ v ] ) {
int s = dfs ( v ) ; // v子树有多少个节点
sum + = s ; // 儿子们的节点个数累加和,再加自己的1, 就是u子树的节点个数sum和
res = max ( res , s ) ; // 猴子选大王
}
}
res = max ( res , n - sum ) ; // 套路:除了自己的所有猴子,还要考虑反向子树
ans = min ( ans , res ) ; // 最大中选最小,就是树的重心
return sum ;
}
int main ( ) {
memset ( h , - 1 , sizeof h ) ;
cin > > n ; // n个顶点
for ( int i = 1 ; i < n ; i + + ) { // n-1条边
int a , b ;
cin > > a > > b ;
add ( a , b ) , add ( b , a ) ;
}
dfs ( 1 ) ;
cout < < ans < < endl ;
return 0 ;
}