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#include <bits/stdc++.h>
using namespace std;
typedef pair<int, int> PII;
const int N = 1e5 + 10, M = 2e5 + 10;
vector<PII> g[N];
int st[M];
int ans[M], al;
int din[N], dout[N];
int op, n, m;
// 需要删边优化
void dfs(int u) {
while (g[u].size()) {
PII x = g[u].back();
g[u].pop_back();
int v = x.first, id = x.second, fid = abs(id);
if (st[fid]) continue;
st[fid] = 1;
dfs(v);
ans[++al] = id; // 记录的是边号
}
}
// 检查是不是存在欧拉回路
bool check() {
int start = 1;
if (op == 2) {
for (int i = 1; i <= n; i++) {
if (din[i] != dout[i]) return 0;
if (din[i]) start = i;
}
} else {
for (int i = 1; i <= n; i++) {
if ((din[i] + dout[i]) & 1) return 0;
if (din[i] + dout[i]) start = i;
}
}
// 判连通,找出欧拉回路
dfs(start);
if (al < m) return 0;
return 1;
}
int main() {
#ifndef ONLINE_JUDGE
freopen("UOJ117.in", "r", stdin);
#endif
scanf("%d %d %d", &op, &n, &m);
for (int i = 1; i <= m; i++) {
int a, b;
scanf("%d%d", &a, &b);
g[a].push_back({b, i}); // 对边点,边号
if (op == 1) g[b].push_back({a, -i}); // 无向图
din[b]++, dout[a]++;
}
if (!check()) {
puts("NO");
return 0;
}
puts("YES");
for (int i = al; i; i--) printf("%d ", ans[i]);
return 0;
}