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68 lines
1.5 KiB
68 lines
1.5 KiB
#include <bits/stdc++.h>
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using namespace std;
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typedef pair<int, int> PII;
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const int N = 1e5 + 10, M = 2e5 + 10;
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vector<PII> g[N];
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int st[M];
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int ans[M], al;
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int din[N], dout[N];
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int op, n, m;
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// 需要删边优化
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void dfs(int u) {
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while (g[u].size()) {
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PII x = g[u].back();
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g[u].pop_back();
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int v = x.first, id = x.second, fid = abs(id);
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if (st[fid]) continue;
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st[fid] = 1;
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dfs(v);
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ans[++al] = id; // 记录的是边号
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}
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}
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// 检查是不是存在欧拉回路
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bool check() {
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int start = 1;
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if (op == 2) {
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for (int i = 1; i <= n; i++) {
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if (din[i] != dout[i]) return 0;
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if (din[i]) start = i;
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}
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} else {
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for (int i = 1; i <= n; i++) {
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if ((din[i] + dout[i]) & 1) return 0;
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if (din[i] + dout[i]) start = i;
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}
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}
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// 判连通,找出欧拉回路
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dfs(start);
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if (al < m) return 0;
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return 1;
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}
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int main() {
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#ifndef ONLINE_JUDGE
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freopen("UOJ117.in", "r", stdin);
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#endif
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scanf("%d %d %d", &op, &n, &m);
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for (int i = 1; i <= m; i++) {
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int a, b;
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scanf("%d%d", &a, &b);
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g[a].push_back({b, i}); // 对边点,边号
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if (op == 1) g[b].push_back({a, -i}); // 无向图
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din[b]++, dout[a]++;
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}
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if (!check()) {
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puts("NO");
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return 0;
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}
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puts("YES");
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for (int i = al; i; i--) printf("%d ", ans[i]);
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return 0;
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} |