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#include <bits/stdc++.h>
using namespace std;
const int N = 210, M = 30010;
int n, m;
int g[N][N], st[N];
int match[N];
int dfs(int x) {
for (int i = 1; i <= n; i++) {
if (g[x][i] && !st[i]) {
st[i] = 1;
int t = match[i];
if (t == -1 || dfs(t)) {
match[i] = x;
return 1;
}
}
}
return 0;
}
int main() {
memset(match, -1, sizeof match);
scanf("%d %d", &n, &m);
while (m--) {
int a, b;
scanf("%d %d", &a, &b);
g[a][b] = 1;
}
// floyd求传递闭包
for (int k = 1; k <= n; k++)
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
g[i][j] |= g[i][k] & g[k][j];
int res = 0;
for (int i = 1; i <= n; i++) {
memset(st, 0, sizeof st);
if (dfs(i)) res++;
}
printf("%d\n", n - res);
return 0;
}