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#include <bits/stdc++.h>
using namespace std;
const int N = 2 * 110, M = 1010;
int n, m, k;
// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
// 匈牙利算法模板
int match[N], st[N];
int find(int u) {
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (!st[v]) {
st[v] = 1;
if (!match[v] || find(match[v])) {
match[v] = u;
return 1;
}
}
}
return 0;
}
int main() {
while (scanf("%d", &n), n) {
scanf("%d %d", &m, &k);
memset(match, 0, sizeof match);
memset(h, -1, sizeof h);
idx = 0;
while (k--) {
int t, a, b;
scanf("%d %d %d", &t, &a, &b);
if (!a || !b) continue; // 0状态不用处理
add(a, b); // 此边是一个任务
}
int res = 0;
for (int i = 1; i < n; i++) {
memset(st, 0, sizeof st);
if (find(i)) res++;
}
printf("%d\n", res);
}
return 0;
}