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#include <bits/stdc++.h>
//UVa 815 Flooding!(排序)
//https://blog.csdn.net/qq_27474589/article/details/75416171
using namespace std;
int a[1000];
int main() {
int m, n, cubi, cnt = 0;
while (~scanf("%d%d", &m, &n) && m && n) {
for (int i = 0; i < m * n; i++) scanf("%d", &a[i]);
scanf("%d", &cubi);
double cub = cubi * 1.0 / 100;
sort(a, a + m * n);
int sum = 0, i = 0, last = 0;
double high, percent;
for (i = 1; i < m * n && (cub - sum) > 0; i++) {
last = sum;
sum += i * (a[i] - a[i - 1]);
}
//高度为零,还需要特判
if (cub == 0) {
high = a[0];
percent = 0;
} else if (i == m * n && (cub - sum) > 0) {//水填满了最高海拔的格子,还有多的水
high = (cub - sum) * 1.0 / i + a[i - 1]; //平分这些水
percent = 100; //100%覆盖
} else {
/*水没有填满最高海拔的格子,在中间时就不够用了。
这里用到sum的上一次结果所以上面for循环中用了last保存。*/
high = (cub - last) * 1.0 / (i - 1) + a[i - 2];
percent = (i - 1) * 1.0 / (m * n) * 100;
}
printf("Region %d\n", ++cnt);
printf("Water level is %.2f meters.\n", high);
printf("%.2f percent of the region is under water.\n\n", percent);//注意空行在最后面
}
return 0;
}