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#include <bits/stdc++.h>
using namespace std;
int n, a[1000086], ans;
int main() {
cin >> n;
a[0] = -1;
a[n + 1] = -1;
for (int i = 1; i <= n; i++) {
cin >> a[i];
if (a[i] == a[i - 1]) {
i--;
n--;
}//没错这是去重。如果重复了,总个数直接减。
}
for (int i = 3; i <= n - 2; i++)//第1、2和倒数第1、2个绝对不是低洼地。
{
if (a[i] < a[i - 1] && a[i] < a[i + 1])ans++;
}
cout << ans;
return 0;
}