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#include <bits/stdc++.h>
//P1204
using namespace std;
double a, b, c, d;
double f(double x) {
return a * x * x * x + b * x * x + c * x + d;//方程部分
}
int main() {
int i;
double x, y, mid;
cin >> a >> b >> c >> d;
for (i = -100; i <= 100; i++)//循环,枚举查找
{
x = i;
y = x + 1;//两个指针
if (f(x) == 0) {
printf("%.2f", x);
cout << " ";
}//如果符合条件则直接输出
else if (f(x) * f(y) < 0)//如果其中有解就开始二分
{
while (y - x >= 0.001)//精度要求
{
mid = (x + y) / 2;
if (f(mid) * f(x) <= 0)y = mid;//判断解在哪个区间
else x = mid;
}
printf("%.2f", x);
cout << " ";
}
}
return 0;
}