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#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int main() {
ll a, b, s = 0, n;
cin >> a >> b;
for (ll y = a; y <= b; y++) {
n = y;//不能改变循环变量的原值,所以要找“替身”
while (n != 0) {
if (n % 10 == 2) s++;
n /= 10;
}
}
cout << s << endl;
return 0;
}