#include #include #include #include #include #include #include #include #include using namespace std; const int N = 1010; int a[N]; /* 测试用例: 1 7 5 6 7 9 12 14 17 输出: i=1,a[7]-a[6]-1=2 i=3,a[5]-a[4]-1=2 i=5,a[3]-a[2]-1=0 i=7,a[1]-a[0]-1=4 Georgia will win */ int main() { int T; scanf("%d", &T); while (T--) { int n, s = 0; scanf("%d", &n); for (int i = 1; i <= n; i++) scanf("%d", &a[i]); sort(a + 1, a + n + 1); /* n=7 a[1~7] = {5 6 7 9 12 14 17} a[7]-a[6]-1=2 1号台阶 √ a[6]-a[5]-1=1 2号台阶 × a[5]-a[4]-1=2 3号台阶 √ a[4]-a[3]-1=1 4号台阶 × a[3]-a[2]-1=0 5号台阶 √ a[2]-a[1]-1=0 6号台阶 × a[1]-a[0]-1=0 7号台阶 √ */ for (int i = 1; i <= n; i += 2) //枚举 奇数阶台阶 { s ^= a[n - i + 1] - a[n - i] - 1; printf("i=%d,a[%d]-a[%d]-1=%d\n", i, n - i + 1, n - i, a[n - i + 1] - a[n - i] - 1); } //异或和为0,先手必败;否则先手必胜 puts(s == 0 ? "Bob will win" : "Georgia will win"); } return 0; }