#include using namespace std; /* 0&(1|0)|(1|1|1&0) 答案:1 (0|1&0|1|1|(1|1))&(0&1&(1|0)|0|1|0)&0 答案:0 */ unordered_map h{{'|', 1}, {'&', 2}}; stack num; stack op; void eval() { int a = num.top(); num.pop(); int b = num.top(); num.pop(); char p = op.top(); op.pop(); int r; if (p == '|') r = b | a; else if (p == '&') r = b & a; num.push(r); } int main() { string s; cin >> s; for (int i = 0; i < s.size(); i++) { if (isdigit(s[i])) num.push(s[i] - '0'); else if (s[i] == '(') op.push(s[i]); else if (s[i] == ')') { while (op.top() != '(') eval(); op.pop(); } else { while (op.size() && h[op.top()] >= h[s[i]]) eval(); op.push(s[i]); } } while (op.size()) eval(); printf("%d\n", num.top()); return 0; }