#include <bits/stdc++.h>
using namespace std;
const int N = 500010, M = N << 1;
#define int long long
int n, m, k;
#define INF 1e18
int sz[N]; // 以u为根节点是否有人
int g[N];  // 从u出发把u子树上的人都送回家再回到u所需要的时间
vector<pair<int, int>> vec[N];
int max1[N]; // u的子树中最长链的长度
int max2[N]; // u的子树中次长链
int up[N];   // 不在u的子树内，距离u最远的那个人的家到u的距离
int id[N];   // 最长链条是哪条链
int ans[N];  // 从u出发把所有点都送回家再回到u的结果

// ans[i] -max(up[i],max1[i]);
void dfs1(int u, int fa) {
    for (auto ts : vec[u]) {
        int v = ts.first;
        int w = ts.second;
        if (v == fa) continue;
        dfs1(v, u);
        if (sz[v]) {
            g[u] += g[v] + 2 * w;
            int now = max1[v] + w;
            if (now >= max1[u]) {
                max2[u] = max1[u];
                max1[u] = now;
                id[u] = v;
            } else if (now >= max2[u]) {
                max2[u] = now;
            }
        }
        sz[u] += sz[v];
    }
}

void dfs2(int u, int fa) {
    for (auto ts : vec[u]) {
        int v = ts.first;
        int w = ts.second;
        if (v == fa) continue;
        if (sz[v] == k) {
            ans[v] = g[v];
            up[v] = 0;
        } else if (sz[v] == 0) {
            ans[v] = ans[u] + 2 * w;
            up[v] = max(up[u], max1[u]) + w;
        } else if (sz[v] && sz[v] != k) {
            ans[v] = ans[u];
            if (id[u] == v) {
                up[v] = max(max2[u], up[u]) + w;
            } else
                up[v] = max(up[u], max1[u]) + w;
        }

        dfs2(v, u);
    }
}

signed main() {
    cin >> n >> k;
    for (int i = 1; i < n; i++) {
        int a, b, c;
        cin >> a >> b >> c;
        vec[a].push_back({b, c});
        vec[b].push_back({a, c});
    }
    for (int i = 1; i <= k; i++) {
        int x;
        cin >> x;
        sz[x] = 1;
    }
    dfs1(1, 0);
    ans[1] = g[1];
    dfs2(1, 0);
    int minn = INF;
    for (int u = 1; u <= n; u++) cout << ans[u] - max(up[u], max1[u]) << endl;
}